4x^2=50,2*(0,1-x)*(0,1-x)

Solution for 4x^2=50,2*(0,1-x)*(0,1-x) equation:

4x^2=50.2(0.1-x)(0.1-x)

We move all terms to the left:

4x^2-(50.2(0.1-x)(0.1-x))=0

We add all the numbers together, and all the variables

4x^2-(50.2(-1x+0.1)(-1x+0.1))=0

We multiply parentheses ..

4x^2-(50.2(+x^2-0.1x-0.1x+0.01))=0


We calculate terms in parentheses: -(50.2(+x^2-0.1x-0.1x+0.01)), so:

50.2(+x^2-0.1x-0.1x+0.01)

We multiply parentheses

50.2x^2+0x+0x+0.502

We add all the numbers together, and all the variables

50.2x^2+2x+0.502

Back to the equation:

-(50.2x^2+2x+0.502)


We get rid of parentheses

4x^2-50.2x^2-2x-0.502=0

We add all the numbers together, and all the variables

-46.2x^2-2x-0.502=0

a = -46.2; b = -2; c = -0.502;
Δ = b2-4ac
Δ = -22-4·(-46.2)·(-0.502)
Δ = -88.7696
Delta is less than zero, so there is no solution for the equation